I am working on mobile number of 9 digits.
I want to use regex to match numbers with pattern 5ABXYXYXY.
A sample I have is 529434343
What I have tried
I have the below pattern to match it.
r"^\d*(\d)(\d)(?:\1\2){2}\d*$"
However, this pattern matches another pattern I have which is 5XXXXXXAB
a sample for that is 555555532.
What I want I want to edit my regex to match the first pattern only 5ABXYXYXY and ignore this one 5XXXXXXAB
CodePudding user response：
You can use
^\d*((\d)(?!\2)\d)\1{2}$
See the regex demo.
Details:
^- start of string\d*- zero or more digits((\d)(?!\2)\d)- Group 1: a digit (captured into Group 2), then another digit (not the same as the preceding one)\1{2}- two occurrences of Group 1 value$- end of string.
CodePudding user response：
To match 5ABXYXYXY where AB should not be same as XY matching 3 times, you may use this regex:
^\d*(\d{2})(?!\1)((\d)(?!\3)\d)\2{2}$
RegEx Breakup:
^: Start\d*: Match 0 or more digits(\d{2}): Match 2 digits and capture in group #1(?!\1): Make sure we don't have same 2 digits at next position(: Start capture group #2(\d): Match and capture a digit in capture group #3(?!\3): Make sure we don't have same digit at next position as in 3rd capture group\d: Match a digit
- )`: End capture group #2
\2{2}: Match 2 pairs of same value as in capture group #2$: End