We have a expression to accept regex with spaces but the pattern should match below examples
ABC1234
TAC4 566
T A C 4 5 6 6
KA C4 56 6
Basically all spaces should be accepted with 3 alpha characters[A-z] and followed by 4 numbers[0-9]
I tried using this regex but it doesnt work :
^((\s)*([a-zA-Z]{3})([0-9]{4}))?$
CodePudding user response：
Assuming no trailing/leading psaces (as per given sample data), the very verbose version could be:
^[A-Z](?: ?[A-Z]){2} ?\d(?: ?\d){3}$
See an online demo. It basically means the same as ^[A-Z] ?[A-Z] ?[A-Z] ?\d ?\d ?\d ?\d$ where:
^- Match start-line anchor;[A-Z]- An uppercase alpha;(?: ?[A-Z]){2}- Non-capture group to match an optional space and an uppercase alpha twice;?\d- Optional space and single digit;(?: ?\d){3}- Non-capture group to match an optional space and a digit three times;$- End-line anchor.
CodePudding user response：
Put \s* after the pattern for letter or number to allow any amount of spaces after that character. Put these in groups so you can then quantify them to allow 3 letters followed by 4 numbers.
^\s*([a-zA-Z]\s*){3}(\d\s*){4}$
CodePudding user response：
/[A-Za-z]\s?[A-Za-z]\s?[A-Za-z]\s?\d\s?\d\s?\d\s?\d/g it's big and inelegant but it'll meet your criteria.