Regex pattern that will not match the brackets at the end of the string-CodePudding

From a large list of text I want to get only these lines:

Ks 2 ... No brackets at the end!
Ks 2 ... (/R)

So from an example as below:

Ks 2 an wo co lo
Ks 2 ni ta ko shi (/R)
Ks 2 fa ki de so (R)
Ks 1 ha lo pa

Pattern should match:

Ks 2 an wo co lo
Ks 2 ni ta ko shi (/R)

I have tried to create something like this: Ks 2(.*)$\/R$|Ks 2(.*)(^($\/R$)$

Can anyone help me how to create this pattern ?!

CodePudding user response：

You can use

^Ks 2.*(?:\(/R\)|[^)])$
^Ks 2.*(?:\(/R\)|(?<!\)))$

See this regex demo (or this demo).

Note: If you deal with multiline texts, add \r? before $ and add (?m) at the start of the pattern. Also, replace [^)] with [^)\n] in the first pattern. E.g. (?m)^Ks 2.*(?:$/R$|[^)\r\n])\r?$ and (?m)^Ks 2.*(?:$/R$|(?<!\)\r?))\r?$.

Details:

^ - start of a string
Ks 2 - a fixed string
.* - any zero or more chars other than line break chars as many as possible
(?:$/R$|[^)]) - either (/R) or a char other than )
$ - end of string.