Split LIST , filename with add domain for each filename-CodePudding

i need help with this function for split a list of filesname with add for each file the site

#!/usr/bin/python3

site = 'http://example.com/'

files = ['Steve.php','Jane.php','Sara.php','Mary.php','Jack.php','Bob.php']

def chunks(l, n):
    for i in range(0, len(l), n):
        yield l[i:i n]

result = list(chunks(files, 2))
print (result)

>>  [['Steve.php', 'Jane.php'], ['Sara.php', 'Mary.php'], ['Jack.php', 'Bob.php']]

but i need like here

1)  ',' and not ', '   ( without space )

and 

2) >> [['http://example.com/Steve.php', 'http://example.com/Jane.php'], ['http://example.com/Sara.php', 'http://example.com/Mary.php'], ['http://example.com/Jack.php', 'http://example.com/Bob.php']]

how i can edit this function ?

Thanks

CodePudding user response：

Thanks so much for ur help, working fine, but still i dont know how to fix this:

['http://example.com/Steve.php', 'http://example.com/Jane.php']

['http://example.com/Steve.php','http://example.com/Jane.php'] without space

CodePudding user response：

I'm not certain but perhaps this is what you want:

site = 'http://example.com/'
files = ['Steve.php','Jane.php','Sara.php','Mary.php','Jack.php','Bob.php']

output = [[site files[i], site files[i 1]] for i in range(0, len(files), 2)]

print(repr(output).replace(' ', ''))

Output:

[['http://example.com/Steve.php','http://example.com/Jane.php'],['http://example.com/Sara.php','http://example.com/Mary.php'],['http://example.com/Jack.php','http://example.com/Bob.php']]

Note:

This will fail if the files list has an odd number of elements

CodePudding user response：

site = 'http://example.com/' 
files = ['Steve.php','Jane.php','Sara.php','Mary.php','Jack.php','Bob.php']  
files = [site   file for file in files] 
files = [files[i:i 2] for i in range(len(files)) if i%2 == 0]

The code above should do the job! I don't know what you mean by the requirement

',' and not ', '

That is simply how python outputs the file.