What does bash -d means and do?-CodePudding

I have a -d option in a bash script but I dont what it does

cp -r ${version} ${version}tm
[ -d "latest-oi" ] rm latest-oi #line 35
[ -d "latest-tm" ] rm latest-tm #line 36
ln -sf "${version}" latest-oi
ln -sf "${version}tm" latest-tm

and when I execute the script I have this error message, I don't know why

./script.sh: line 35: [: missing `]'
./script.sh: line 36: [: missing `]'

I would like to know what -d means and what it does and why there is an error when the script is executed, Thanks

CodePudding user response：

I don't see any -d option to your bash, but to the command [. See man test for this command. If you want to have two commands in the same line, you have use a command separator between them. Valid command separators are a newline, a ;, a && or a ||.

If you write a

[ -d "latest-oi" ] && rm latest-oi

it means that the rm is executed if [ returns exit code zero. Another way to write it would be

test -d latest-oi && rm latest-oi

If you would use a || instead, the rm would be executed whenever [ returns non-zero exit code.