How to create a loop which checks if each character in argument is an integer?-CodePudding

learning python 2.6 and i can't seem to figure out how to make this code simpler.

def check_csc(code):
    cod=list(code)

    if len(cod)==3:
        if (cod[0]=='0' or cod[0]=='1' or cod[0]=='2' or cod[0]=='3' or cod[0]=='4' or cod[0]=='5' or cod[0]=='6' or cod[0]=='7' or cod[0]=='8' or cod[0]=='9') and (cod[1]=='0' or cod[1]=='1' or cod[1]=='2' or cod[1]=='3' or cod[1]=='4' or cod[1]=='5' or cod[1]=='6' or cod[1]=='7' or cod[1]=='8' or cod[1]=='9') and (cod[2]=='0' or cod[2]=='1' or cod[2]=='2' or cod[2]=='3' or cod[2]=='4' or cod[2]=='5' or cod[2]=='6' or cod[2]=='7' or cod[2]=='8' or cod[2]=='9'):
            return True
        else:
            return False
    else:
        return False

basically the argument must be less than 999, all integers (obviously) and must be 3 integers.

CodePudding user response：

what is example of parameter?

def check_csc(code):
    if int(code) <= 999:
        return True
    return False

print(check_csc('999')) # True

CodePudding user response：

def check_csc(code):
    if str(code).isdigit() and 100 <= code <= 999:
        return True
    else:
        return False