How to sort a list of items by one of its component dimensions-CodePudding

this is my first question in stackoverflow. Hope I'm clear.

I would like to transform the following list (sorted ascending by the first element of each item):

[[7, 4], [9, 4], [10, 1]]

into this(sorted descending by the second element of each item, then descending by the first element):

[[9, 4], [7, 4], [10, 1]]

I have tried the sort attribute with no success. Any hint? thks

CodePudding user response：

To customize sorting behavior, you can provide the key keyword argument in sorted() or list.sort(). In OP's case, they key argument should be a function that takes in one item in the original list (i.e., a pair of numbers like [7, 4]) and then returns the pair of numbers reversed (i.e., [4, 7]). We need to reverse the sort because by default, the sorted() and list.sort() sort in from smallest to largest.

See more about sorting in python, and in particular the key functions, at https://docs.python.org/3/howto/sorting.html#key-functions.

original = [[7, 4], [9, 4], [10, 1]]
desired = [[9, 4], [7, 4], [10, 1]]

original_sorted = sorted(
    original, 
    key=lambda pair: (pair[1], pair[0]), reverse=True)

original_sorted == desired  # True

The lambda is a function. It is equivalent to the function below. We use a lambda here because it is compact and we do not need to refer to this function anywhere else.

def key_function(pair):
    return pair[1], pair[0]