I had trying to make a Flask application. I want make some file like this:

# ...
@app.route("/search") # Because Lynx can't play JavaScript
def search():
    # Return an 202 Accepted
    # Very long times searching...
    # Return result
# ...

So how can I let it return a 202 Accepted but don't return from the function?

CodePudding user response：

from threading import Thread

@app.route("/search"):
def search():
    def my_thread():
        # Search
        # Store the result somewhere so that a separate request
        # can be done to get result
    thread = Thread(target=my_thread)
    thread.start()
    return "Long request", 202

You might want to use something like Celery, it's built for doing asynchronous tasks

CodePudding user response：

return a 202 Accepted but don't return from the function

This is impossible, as python docs put it

return leaves the current function call with the expression list (or None) as return value.

So return does terminates function, this does hold for python as whole (is not limited to flask)