Hi I'am totally new to programmering and i have just jumped into it.
The problem i am trying to solve is to make a function that standardized an adress as input.
example:
def standardize_address(a):
numbers =[]
letters = []
a.replace('_', ' ')
for word in a.split():
if word. isdigit():
numbers. append(int(word))
elif word.isalpha():
letters.append(word)
s = f"{numbers} {letters}"
return s
Can someone help me explain my error and give me a "pro" programmers solution and "noob" (myself) solution?
This is what i should print:
a = 'New_York 10001'
s = standardize_address(a)
print(s)
and the output should be:
10001 New York
Right now my output is:
[10001] ['New', 'York']
CodePudding user response:
Issues
strings are immutable so you need to keep the replace result, so do
a = a.replace('_', ' ')or chain it before the split callYou need to concatenate the lists into one
numbers lettersthen join the elements with" ".join()don't convert the numeric to
int, that's useless and would force you to convert them back to str in the" ".join
def standardize_address(a):
numbers = []
letters = []
for word in a.replace('_', ' ').split():
if word.isdigit():
numbers.append(word)
elif word.isalpha():
letters.append(word)
return ' '.join(numbers letters)
Improve
In fact you want to sort the words regarding the isdigit condition, so you can express that with a sort and the appropriate sorted
def standardize_address(value):
return ' '.join(sorted(value.replace('_', ' ').split(),
key=str.isdigit, reverse=True))
CodePudding user response:
numbers and letters are both lists of strings, and if you format them they'll be rendered with []s and ''s appropriately. What you want to do is to replace this:
s = f"{numbers} {letters}"
return s
with this:
return ' '.join(numbers letters)
numbers letters is the combined list of number-strings and letter-strings, and ' '.join() takes that list and turns it into a string by putting ' ' between each item.
