Is there a way to use sed (with potential other command) to transform all the keys in a file that lists key-values like that :

a.key.one-example=a_value_one
a.key.two-example=a_value_two

and I want that

A_KEY_ONE_EXAMPLE=a_value_one
A_KEY_TWO_EXAMPLE=a_value_two

What I did so far : sed -e 's/^[^=]*/\U&/'

it produced this :

A.KEY.ONE-EXAMPLE=a_value_one
A.KEY.TWO-EXAMPLE=a_value_two

But I still need to replace the "." and "-" on left part of the "=". I don't think it is the right way to do it.

CodePudding user response：

It should be done very easily done in awk. awk is the better tool IMHO for this task, it keeps it simple and easy.

awk 'BEGIN{FS=OFS="="} {$1=toupper($1);gsub(/[.-]/,"_",$1)} 1' Input_file

Simple explanation:

• Make field separator and output field separator as =
• Then use awk's default function named toupper which will make $1(first field) upper case and save it into $1 itself.
• Using gsub to substitute . OR - with _ in $1 as per requirement.
• use 1 which is idiomatic way to print a line in awk.

CodePudding user response：

You can use

sed ':a;s/^\([^=]*\)[.-]\([^=]*\)/\U\1_\2/g;ta' file > newfile

Details:

• :a - sets an a label
• s/^\([^=]*\)[.-]\([^=]*\)/\U\1_\2/g - replaces ^\([^=]*\)[.-]\([^=]*\) pattern that matches
  • ^ - start of string
  • \([^=]*\) - Group 1 (\1): any zero or more chars other than =
  • [.-] - a dot or hyphen
  • \([^=]*\) - Group 2 (\2): any zero or more chars other than =
• ta - jumps back to a label position upon successful replacement
  and replaces with Group 2 _ Group 1

See the online demo:

#!/bin/bash
s='a.key.one-example=a_value_one
a.key.two-example=a_value_two'
sed ':a;s/^\([^=]*\)[.-]\([^=]*\)/\U\1_\2/g;ta' <<< "$s"

Output:

A_KEY_ONE_EXAMPLE=a_value_one
A_KEY_TWO_EXAMPLE=a_value_two