define in c get the value of parameter-CodePudding

I want to create a program that will print the value of the three parameter by using define in c

#include <stdio.h>
#define Print(num) printf("%d",n##num)
int main()
{
    int i;
    int n1=1, n2=2, n3=3;
    for(i=1;i<=3;i  )Print(i);
}

the problem than n##num equal to ni and to n1,n2,n3. is there a way to get the values of i to set in num instead of "i"?

CodePudding user response：

The preprocessor runs before the code is even compiled. You can't do loops in the preprocessor like that.

What you really want is an array:

#include <stdio.h>

int main()
{
    int i;
    int n[] = { 1, 2, 3 };
    for(i=0;i<3;i  ) printf("%d\n", n[i]);
}