I am automating a website, and it has multiple searchboxes with the same title, class, etc. It usually occurs 2 or 3 times on every page. Is there a way in which I can tell Selenium to only use the 2nd or 3rd occurrence?

I currently have this:

driver.find_element(By.XPATH, './/*[@title = "Searchbox"]').click()

And

driver.find_element(By.XPATH, './/*[@title = "Searchbox"]').send_keys(i)

It currently clicks the first searchbox and types number i, but I want Selenium to do this for any other searchbox with the same html.

Thanks!

CodePudding user response：

To get some element by it's occurrence using xpath just wrap the xpath in (<your xpath>)[number] where number is the element occurrence number.

For click the second one:

driver.find_element(By.XPATH, '(.//*[@title = "Searchbox"])[2]').click()

CodePudding user response：

Ideally your locator strategy should identify each and every WebElement uniquely within the DOM Tree.

As your Locator Strategy identifies 2 or 3 elements on every page, you need to construct a more canonical locator. However the following line of code:

driver.find_element(By.XPATH, './/*[@title = "Searchbox"]')

will always select the first matching element.

To click on the second and third matching element, you can use the following locator strategies:

• To click on second match:

  driver.find_element(By.XPATH, "(.//*[@title = "Searchbox"])[1]").click()
  

• To click on third:

  driver.find_element(By.XPATH, "(.//*[@title = "Searchbox"])[2]").click()
  

CodePudding user response：

As a last resort you can use xpath indexing:

if this .//*[@title = "Searchbox"] represent 1/3 nodes or 1/2 nodes

you can simply change it to

(.//*[@title = "Searchbox"])[2] 

and use it like this:

driver.find_element(By.XPATH, "(.//*[@title = 'Searchbox'])[2]").send_keys(i)

to represent 2nd node

or [3] to represent 3rd node.

(.//*[@title = "Searchbox"])[3]

and so on....

This is not recommended but can be used as a last resort.