How to turn a Json output of Multiple URLs into a list-CodePudding

I am parsing data through a json file and obtaining multiple URLs, around 50.

below is part of the command I used to pull out just the URLs

results = json.loads(results)
    for repo in results:
        DevOps_url = (repo['remoteUrl'])
        print(DevOps_url)

The output looks something like this:

https://sjdfnlajsdfljhasdfajdfhlkajsdfhajsdfhlajksdfh

etc.

How can I grab those URLs and put them all into one list so I can parse through the list for each URL? I have tried the .split() method and that just puts each individual URL into its own list and thats not what I want.

I want it to look something like this ["url","url","url",etc.] in the output.

Any help would be appreciated!

CodePudding user response：

You could use append to add urls from loop to new list:

results = json.loads(results)

all_urls = []
for repo in results:
    all_urls.append(repo['remoteUrl'])

Also you could use list comprehension to do the same in one line:

results = json.loads(results)
    
all_urls = [repo['remoteUrl'] for repo in results]

Then you could iterate over created urls with for loop like so:

for url in all_urls:
    print(url)

CodePudding user response：

It could help you:

import json;

file = open("./json.json")
loaded = json.load(file);
file.close()

# List for each value of json's key
list_of_content = []

# Get all keys of the json file and their value
for key in loaded:
    list_of_content.append(loaded[key])

for an_value in list_of_content:
    #Do something with each value...
    print(type(an_value))
    print(an_value)
    # etc...