How to combine arrays and repeat first array's elments as many times as the length of the secon-CodePudding

The challenge is to build a table. So, the first array is like to the following:

[1001,235689,1002,235690,1003,235691]

The second array is like this:

[
[tecido,1,Crepe Georgette,,,,mt,0.9,11.9,10.71],
[tecido,2,Forro,,,,kg,0.5,7.916666666666667,3.9583333333333335],
[aviamento,5,Tag Láureen Instrução Lavagem,,,,und,1,0.5,0.5],
[aviamento,3,Entretela malha,,,,und,1,10,10]
]

How can I concatenate them to be like:

[
[1001,235689,tecido,1,Crepe Georgette,,,,mt,0.9,11.9,10.71],
[1001,235689,tecido,2,Forro,,,,kg,0.5,7.916666666666667,3.9583333333333335],
[1001,235689,aviamento,5,Tag Láureen Instrução Lavagem,,,,und,1,0.5,0.5],
[1001,235689,aviamento,3,Entretela malha,,,,und,1,10,10]
]

I've tried looping over the first array and get the second in, but I get lost repeating the first array's elements as many times as the elements count in the second.

Appreciate any help.

CodePudding user response：

You can simply map() the second array returning each array prepended by the first two elements of the first, here creating a single slice() beforehand and spreading it into each array in the map.

const arr1 = [1001, 235689, 1002, 235690, 1003, 235691];
const arr2 = [['tecido', 1, 'Crepe Georgette', , , , 'mt', 0.9, 11.9, 10.71], ['tecido', 2, 'Forro', , , , 'kg', 0.5, 7.916666666666667, 3.9583333333333335,], ['aviamento', 5, 'Tag Láureen Instrução Lavagem', , , , 'und', 1, 0.5, 0.5], ['aviamento', 3, 'Entretela malha', , , , 'und', 1, 10, 10],];

const prepend = arr1.slice(0, 2);
const result = arr2.map((arr) => [...prepend, ...arr]);

result.forEach(a => console.log(a.join(', ')));

CodePudding user response：

Since you are using two elements from the firstArray for each row, you'll need to iterate through it two at a time, which prevents use of most array methods, so a good old for loop:

let output = [];

for (let i=0; i < firstArray.length; i =2) {
  secondArray.forEach(el => {
    output.push([firstArray[i], firstArray[i   1], ...el]);
  });
}

console.log(output);

CodePudding user response：

Try this:

function test_07() {
  try {
    var a = [1001,235689,1002,235690,1003,235691];
    var b = [["tecido",1,"Crepe Georgette",,,,"mt",0.9,11.9,10.71],
              ["tecido",2,"Forro",,,,"kg",0.5,7.916666666666667,3.9583333333333335],
              ["aviamento",5,"Tag Láureen Instrução Lavagem",,,,"und",1,0.5,0.5],
              ["aviamento",3,"Entretela malha",,,,"und",1,10,10]];
    var c = [];
    for( var i=0; i<b.length; i   ) {
      c.push(a.concat(b[i]));
    }
    console.log(c)
  }
  catch(err) {
    console.log(err);
  }
}

CodePudding user response：

Maybe this one?

let arr1 = [1001,235689,1002,235690,1003,235691]

let arr2=[["tecido",1,"Crepe Georgette",,,,"mt",0.9,11.9,10.71], ["tecido",2,"Forro",,,,"kg",0.5,7.916666666666667,3.9583333333333335],
 ["aviamento",5,"Tag Láureen Instrução Lavagem",,,,"und",1,0.5,0.5],
    ["aviamento",3,"Entretela malha",,,,"und",1,10,10]];
let arr3 = []
for (let i = 0;i<arr1.length;i =2){
for(let y in arr2){
let little = [arr1[i],arr1[i 1]]
arr3.push(little.concat(arr2[y]))
}
}
console.log(arr3)

CodePudding user response：

I think this is what you are asking

function myfunk1() {
  const a = ['a', 'b', 'c', 'd', 'e', 'f', 'g'];//create a table with row length of a
  const g = ['a', 'b', 'c', 'd'];
  const h = ['a', 'b', 'c', 'd', 'e', 'f', 'g','h','i'];
  let b = [];
  b.push(a);
  Logger.log('With Just A: %s', JSON.stringify(b));
  let c = [...Array.from(new Array(a.length).keys(), x => x)];//creates another array of length a
  b.push(c);
  Logger.log('With a and c: %s', JSON.stringify(b));
  let d = [...Array.from(new Array(a.length).keys(), x => '')];//creates another array of length a
  b.push(d);
  Logger.log('With a and c and d: %s', JSON.stringify(b));
  let e = [...Array.from(new Array(a.length).keys(), x => g[x] ? g[x] : '')];//creates another array of length a
  b.push(e);
  Logger.log('With a and c,d and e: %s', JSON.stringify(b));
  let f = [...Array.from(new Array(a.length).keys(), x => h[x] ? h[x] : '')];//creates another array of length a
  b.push(f);
  Logger.log('With a and c,d and e: %s', JSON.stringify(b));
}

Execution log
2:29:57 PM  Notice  Execution started
2:29:56 PM  Info    With Just A: [["a","b","c","d","e","f","g"]]
2:29:56 PM  Info    With a and c: [["a","b","c","d","e","f","g"],[0,1,2,3,4,5,6]]
2:29:56 PM  Info    With a and c and d: [["a","b","c","d","e","f","g"],[0,1,2,3,4,5,6],["","","","","","",""]]
2:29:56 PM  Info    With a and c,d and e: [["a","b","c","d","e","f","g"],[0,1,2,3,4,5,6],["","","","","","",""],["a","b","c","d","","",""]]
2:29:56 PM  Info    With a and c,d,e and f: [["a","b","c","d","e","f","g"],[0,1,2,3,4,5,6],["","","","","","",""],["a","b","c","d","","",""],["a","b","c","d","e","f","g"]]
2:29:58 PM  Notice  Execution completed

Array.from;