Appreciate if you can advise and share how to build Absolute function without using abs() or loop (if/else) , just work with operators (C )

CodePudding user response：

template<typename N>
N abs(const N& n)
{
    const N arr[2] = {n, -n};
    return arr[n < 0];
}

is one way. And it won't dump the pipeline either.

CodePudding user response：

I can offer the solution of your problem.

#include <iostream>
using namespace std;
int absolute(int number)
{
    return number<0 ? -number : number;
}
int main()
{
    int number;
    cin>>number;
    cout<<absolute(number);
    return 0;
}

Input:

-4

Output:

4

Input:

4

Output:

4

CodePudding user response：

There is another way using a C 20 concept:

#include <iostream>
#include <concepts>


auto abs( std::integral auto num )
{
    return num < 0 ? -num : num;
}

int main( )
{
    std::cout << abs( -4 ) << ' ' << abs( 12345 ) << '\n';
}