Make only identical pairs in python list-CodePudding

How to create pairs in python list . list = [1,2,3,4,5,6,7] i want to compare (1,2),(3,4) (5,6)

identical pairs comparison

how can we loop through all the pairs

CodePudding user response：

You can use zip and slice the input list every two items with different starting points:

lst = [1,2,3,4,5,6,7]

list(zip(lst[::2], lst[1::2]))

output: [(1, 2), (3, 4), (5, 6)]

CodePudding user response：

if I understand you correctly, you want to take the list and create all possible pairs. To do that you should use itertools

Take a look at the following topic: How to split a list into pairs in all possible ways

matt@stanley:~$ python
Python 2.6.5 (r265:79063, Apr 16 2010, 13:57:41) 
[GCC 4.4.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import itertools
>>> list(itertools.combinations(range(6), 2))
[(0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (1, 2), (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 4), (3, 5), (4, 5)]

CodePudding user response：

you could do something like this:

list = [1,2,3,4,5,6,7]
def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in range(0, len(lst), n):yield lst[i:i   n]    
sublist = [x for x in chunks(list, 2)]
for x in sublist:
    if x.__len__() > 1:continue
    else:sublist.remove(x)
print(sublist)

Output:

[[1,2],[3,4],[5,6]]

CodePudding user response：

It will use a moving cursor for slicing to get the value.

def func(l):
    prev_i, i = 0, 2
    while True:
        current = l[prev_i: i]
        if len(current) < 2:
            break
        yield current
        prev_i, i = i, i   2


print(list(func([1,2,3,4,5,6,7])))

Output:

[[1, 2], [3, 4], [5, 6]]