I have an array
data = [
{code: 'A1', name: 'bag', qty: 3},
{code: 'A2', name: 'purse', qty: 2},
{code: 'A3', name: 'belt', qty: 1},
]
I want to omit qty & duplicate each item to another array based on each qty :
data = [
{code: 'A1', name: 'bag'},
{code: 'A1', name: 'bag'},
{code: 'A1', name: 'bag'},
{code: 'A2', name: 'purse'},
{code: 'A2', name: 'purse'},
{code: 'A3', name: 'belt'},
]
I've tried :
const [qtyList, setQtyList] = useState(
new Array(renderData.length).fill(1)
);
const [selectedProduct, setSelectedProduct] = useState([])
const updatedQty = qtyList.map((q, index) => {
if (index === k) return q = parseInt(val)
else return q
});
setQtyList(updatedQty); //[3,2,1]
data.map((i, idx) => {
let temp = []
let existed = data.filter(x=>x.code==i.code).length
for (let x=0; x<=qtyList[idx]; x ){
temp.push(i)
}
setSelectedProduct((prev)=> [...prev, i])
}
CodePudding user response:
Use the following code:
var data = [
{ code: 'A1', name: 'bag', qty: 3 },
{ code: 'A2', name: 'purse', qty: 2 },
{ code: 'A3', name: 'belt', qty: 1 },
];
var newArray = data.map(x => {
return Array(x.qty).fill({ code: x.code, name: x.name })
})
console.log([].concat.apply([], newArray))
CodePudding user response:
my approach using reduce
let data = [
{code: 'A1', name: 'bag', qty: 3},
{code: 'A2', name: 'purse', qty: 2},
{code: 'A3', name: 'belt', qty: 1},
]
let a = data.reduce((acc,curr)=>{
const {code,name,qty} = curr;
for (let i = 0; i < qty; i ) {
acc.push({code,name});
}
return acc;
},[])
console.log(a)
CodePudding user response:
data.map(item => Array(item.qty).fill({ code: item.code, name: item.name })).flat();
CodePudding user response:
There is probably a more elegant solution to this problem, but this was my quick fix:
let data = [
{code: 'A1', name: 'bag', qty: 3},
{code: 'A2', name: 'purse', qty: 2},
{code: 'A3', name: 'belt', qty: 1},
]
let dupArr = []
data.map((i) =>{
for(let j = 0;j<= i['qty']-1; j ){
dupArr.push(i);
}
});
dupArr.map((idx)=>{
delete idx['qty'];
})
CodePudding user response:
Use this code
data.reduce((a,{qty, ...rest})=>a.concat(Array(qty).fill({...rest})),[]);
