Sort a list of words in the order of indices-CodePudding

I'm working on this program and I am currently stuck on this issue. I have been given a list of words and also a list of indices and I was wondering if anyone could help me write a simple function to join the list of words together in the order of the indices given. The first argument would be the list of words:

['boy', clown, 'a', 'saw']

The second argument would be the list of indices:

[2, 0, 3, 2, 1]

The expected outcome would be " a boy saw a clown". Any help is appreciated although Id prefer not using list comprehension and would rather go with a for loop with some combination of indexing for example.

CodePudding user response：

This is easily achieved with a list comprehension:

words   = ['boy', 'clown', 'a', 'saw']
indices = [2, 0, 3, 2, 1]
results = [words[i] for i in indices]

CodePudding user response：

Using a for loop:

words   = ['boy', 'clown', 'a', 'saw']
indices = [2, 0, 3, 2, 1]
output = []

for i in indices:
    output.append(words[i])
print(' '.join(output))

CodePudding user response：

Using a function and a loop:

def get_line(words, indices):
    line = ''
    for i, index in enumerate(indices):
        line  = words[index]
        if i != len(indices) - 1:
            line  = " "
    return line


print(get_line(['boy', 'clown', 'a', 'saw'], [2, 0, 3, 2, 1]))

Output:

a boy saw a clown

Disclaimer:

The other two answers (list comprehensions and appending to a list) are better than this. I added this as an alternative solution.