How to remove days from datetime.date object-CodePudding

Let's say, we have this date 2022-01-01. How can I remove days part from it to get 2022-01?

I've already tried using strptime '{:%Y-%m}'.format(dt.strptime(currentDate, '%Y-%m-%d')) but it gives me this error TypeError: strptime() argument 1 must be str, not datetime.date

CodePudding user response：

Use strftime method:

import datetime as dt

date_object = dt.datetime(2022, 1, 1)

output = date_object.strftime('%Y-%m')
print(output) # 2022-01

CodePudding user response：

from datetime import datetime

dt: datetime = datetime.strptime("2022-01-01", "%Y-%m-%d")
print(dt.strftime("%Y-%m"))
# 2022-01