a = '\xe6\xb8\xac\xe8\xa9\xa6'
print(bytes(a, 'latin-1').decode('utf-8'))
a = input("input:")
print(bytes(a, 'latin-1').decode('utf-8'))
The first one can print out the result correctly
While the second one will just print out the string I entered
output:
測試
input:\xe6\xb8\xac\xe8\xa9\xa6
\xe6\xb8\xac\xe8\xa9\xa6
Process finished with exit code 0
CodePudding user response:
The transformation is a bit tricky:
# Use r'', simulate input
a = r'\xe6\xb8\xac\xe8\xa9\xa6'
print(a.encode('ascii').decode('unicode-escape').encode('latin-1').decode('utf-8'))
Follow the transformation:
# Step 0 (initial)
print(a)
\xe6\xb8\xac\xe8\xa9\xa6
# Step 1
print(a.encode('ascii'))
b'\\xe6\\xb8\\xac\\xe8\\xa9\\xa6'
# Step 2
print(a.encode('ascii').decode('unicode-escape'))
測試
# Step 3
print(a.encode('ascii').decode('unicode-escape').encode('latin-1'))
b'\xe6\xb8\xac\xe8\xa9\xa6'
# Step 4 (final)
print(a.encode('ascii').decode('unicode-escape').encode('latin-1').decode('utf-8'))
測試
CodePudding user response:
Alternatively, use this simpler method (at least if you are not worried about security risks):
unicode_input = eval('"' input() '"')
Keep in mind: using eval has high security risks
or as suggested by @MisterMiyagi:
import ast
unicode_input = ast.literal_eval('"' input() '"')
