What is the difference between size() and max_size() functions for std: :array in C ?

  array<int,5> arr{ 1, 2, 3, 4, 5 }; 
  cout << arr.size(); 
  /* Output : 5 */ 
  
 array<int, 5> arr{ 1, 2, 3, 4, 5 }; 
 cout << arr.max_size(); 
 /* Output : 5 */

CodePudding user response：

What is the difference between size() and max_size() functions for std: :array in C ?

The latter has prefix max_. There is no other practical difference between them for std::array.

The difference is conceptual. size is the current number of elements in the container, and max_size is a theoretical upper bound to how many elements the container could have. Since the number of elements in std::array is constant, the current number of elements is exactly the same as the number of elements there can ever be. For other containers, there is a practical difference.

Using the max_size member function of std::array is conceptually silly. It exists so that std::array conforms to the Container concept (e.g. named requirement) which allows it to be used uniformly with other containers which is useful within templates.

CodePudding user response：

i think max_size() refers to the capacity of the array and not the actual size of the array.