How to find at which line is there a match for list comparison (PYTHON)-CodePudding

A = [['0', '6', '4', '3'], ['0', '2', '8', '3'], ['0', '4', '1', '5'], ['0', '3', '2', '5']]

B = ['0', '4', '1', '5']

Say I want to find out at which line does B equal to the list. How do I write a solution for this?

The answer would be the third line.

I tried doing a for loop.

CodePudding user response：

You can try list.index(element) to get the index of the element in the original list (A). In your terminology, to get the line just add one to the index.

line = A.index(B)   1

CodePudding user response：

you dont need use loops.you can get the element index by indexing.

A = [['0', '6', '4', '3'], ['0', '2', '8', '3'], ['0', '4', '1', '5'], ['0', '3', '2', '5']]

B = ['0', '4', '1', '5']

print(A.index(B))

>>> 2