How to search end of the digit from this two srting which is 0.12%?

text1 = '20% of the modern marijuana terpene profile. Myrcene has a distinct earthy, musky flavor, resembling cloves. It is responsible for calming and soothing effects of weed. Myrcene is also found in hops, thyme, mango, lemongrass, guava melon.     0.12%'



text2 = 'The modern marijuana terpene profile. Myrcene has a distinct earthy, musky flavor, resembling cloves. It is responsible for calming and soothing effects of weed. Myrcene is also found in hops, thyme, mango, lemongrass, guava melon.     0.12%'

I tried this which worked for text2 but not getting expected result for text1 like text2

re.search(r'(\d.*)',text)

but my expected result will be 0.12% only

CodePudding user response：

Using (\d.*) captures the first encounter of a digit followed by the rest of the line.

To match the digit with an optional decimal part followed by a percentage sign at the end of the string:

\b\d (?:\.\d )?%$

Explanation

• \b A word boundary to prevent a partial word match
• \d (?:\.\d )? Match 1 digits with an optional decimal part
• % Match literally
• $ End of string

Regex demo

CodePudding user response：

\b\d (?:\.\d )?%$

This should work.

\b Returns a match where the specified characters are at the beginning or at the end of a word

\d Returns a match where the string contains digits (numbers from 0-9) [Checks for digits basically]

One or more occurrences

() Capture and group

• ? Zero or one occurrences
• \d Returns a match where the string contains digits (numbers from 0-9)
• One or more occurrences

? Zero or one occurrences

%$ Checks if ends with %

Some explanation taken from w3schools