Removing rows that contain empty column without pandas-CodePudding

a_list = [ ["a", ""], ["b", "2"] ]

I have a list of lists as written above. Any suggestions on how to remove the row that contains an empty element (in this case the first list), without using pandas, so it returns:

a_list = [ ["b", "2"] ]

CodePudding user response：

Try:

a_list = [["a", ""], ["b", "2"]]

a_list = [l for l in a_list if "" not in l]
print(a_list)

Prints:

[['b', '2']]

CodePudding user response：

To check at specific index too

Here in your case you're check list[xx][1] index

solution-1

#Devil 
a_list = [["a", ""], ["b", "2"]]
a_list = [l for l in a_list if l[1] != ""]
print(a_list)

solution 2

Use another array and append the data init

new = []
for i in l:
    if i[1] != "":
        new.append(i)
print(new)