Python Loop support-CodePudding

Hi everyone I have this task: Write a python program that takes two numeric inputs x and y.

a) [5 pts] The program should take numeric inputs continuously.

b) [10 pts] The program should ensure the range of x and y is between 0 and 1. If either one of the input values is out of range, smaller than 0 or greater than 1, then the program should quit.

c) [10 pts] Implement XOR gate, where the program returns 1 if both x and y values are different; otherwise, it returns 0.

The program should work for floating-point values.

For example,

If x = .3 and y = .3, then xor output should be 0

If x = .6 and y = .3, then xor output should be 1

If x = .3 and y = .6, then xor output should be 1

If x = .6 and y = .6, then xor output should be 0

So far I have done this but I still keep getting errors

x=float(input("enter x: "))

y=float(input("enter y : "))
while True:

  if(x>=0 and x<=1) and (y>=0 and y<=1):
        def XOR (x, y):
            if x != y:
              return 1
            else:  return 0
  print(XOR(x,y))
continue 
  elif(x>=0 and x<=1) and (y>=0 and y<=1): 
        break

I get this error

 File "<ipython-input-337-80599671f24c>", line 13
    elif(x>=0 and x<=1) and (y>=0 and y<=1):
    ^
IndentationError: unexpected indent

CodePudding user response：

It looks like your indentation is off the continue and print statements should be at the same indentation level as function definition above like:

x=float(input("enter x: "))

y=float(input("enter y : "))
while True:
    if(x>=0 and x<=1) and (y>=0 and y<=1):
        def XOR (x, y):
            if x != y:
                return 1
            else:
                return 0
        print(XOR(x,y))
        continue 
    elif(x>=0 and x<=1) and (y>=0 and y<=1): 
        break

though the XOR function should be defined outside the loop and the continue statement is redundant

def XOR (x, y):
    if x != y:
        return 1
    else:
        return 0


x=float(input("enter x: "))

y=float(input("enter y : "))
while True:
    if(x>=0 and x<=1) and (y>=0 and y<=1):
        print(XOR(x,y))
    elif(x>=0 and x<=1) and (y>=0 and y<=1): 
        break

in order to have the user repeatedly prompted for input the input lines should be within the loop and the elif statement should be an else statement either the condition is met and the function is run and the user prompted for another input or the loop exits

def XOR (x, y):
    if x != y:
        return 1
    else:
        return 0


while True:
    x=float(input("enter x: "))
    y=float(input("enter y : "))
    if(x>=0 and x<=1) and (y>=0 and y<=1):
        print(XOR(x,y))
    else: 
        break

CodePudding user response：

Define your function outside of the loop and get the input in the loop.

def xor(x, y):
    return x != y

while True:
    x = float(input("enter x: "))
    y = float(input("enter y: "))
    if not (0 <= x <= 1 and 0 <= y <= 1):
        break
    print(xor(x, y))