Find item if exist in deep nested children array?-CodePudding

I need to find if item exist in deep nested array.

example of array

let arr = [
  {
   id: 1 ,
   title : 'Test' ,
   children: 
  [
    {id: 1 , title: 'Title' , hasChild : true },
    {id: 1 , title: 'Title' , hasChild : false },
    {id: 1 , title: 'Title' },
  ] 
 },
]

I need to looping thought arr.children and find if has property with name hasChild find item and set it on false.

After looping i need to get array like ->

example of array

let arr = [
  {
   id: 1 ,
   title : 'Test' ,
   children: 
  [
    {id: 1 , title: 'Title' , hasChild : false }, //here is changed hasChild to false
    {id: 1 , title: 'Title' , hasChild : false },
    {id: 1 , title: 'Title' },
  ] 
 },
]

I am find way but i need better solution :

    arr.map(it) => {
      if (it.hasChild) {
        it.dashCheck = false; 
      }
    });

CodePudding user response：

You can use recursive functions to make operations on inifitely nested objects/arrays etc.

function recursiveUpdate(array, index) {
  const element = array[index];
  if(!element) return;
  if(Object.keys(element).indexOf('children') > -1) {
    element.hasChild = true;
    recursiveUpdate(element['children'], 0);
  } else {
    element.hasChild = false;
    recursiveUpdate(array, index 1);
  }
}

recursiveUpdate(arr, 0);

CodePudding user response：

If the structure of arr is always like the one you mentioned in your question, you could simple iterate over the children by using the forEach method of the Array class:

arr.forEach(item => {
  item.children.forEach(child => {
    child.hasChild = child.hasChild === true ? false : child.hasChild;
  });
});

Note: This will alter the original array and not create a copy with the altered value for hasChild.