I would like to clear our first string in the quotes of this example:

set dstaddr "somename 10.108.41.90" "somename 10.108.148.53" 

I would like following result:

set dstaddr "somename 10.108.148.53" 

Could you please suggest how to to achieve it in bash? I am not interested only to remove first match in quotes but I am interested to remove matched IP address ranges from 10.108.41.0/24 or those that contain 41 in the third octet along with their names and remove them.

Logic should be : Okey script if you find hosts within subnet 10.108.41.0/24 please remove them from the string along with their names but do not touch other objects.

CodePudding user response：

Perl:

echo 'set dstaddr "somename 10.108.41.90" "somename 10.108.148.53"' \
| perl -pe 's/\b(\S )\b.*?\1/$1/'

set dstaddr "somename 10.108.148.53"

• \b(\S )\b finds a word and remembers it
• .*?\1 finds some characters followed by that word
• s/pattern/$1/ replaces the patten with the captured word

CodePudding user response：

What about this:

awk '{print $1 " " $2 " " $5 " " $6}' test.txt

I simply use the space as a delimiter for the awk command. This obviously only works if somename does not contain any space character.