How to write function that take a list and number X .If X exist in list in index ‘m’, it should retu-CodePudding

def func(x):
    lst=list(map(int,input("Enter a list of numbers: ").split()))
    flag=0
    num=0
    for i in lst:
         if x==i:
                flag=1
                
    if flag==1:
        ab=lst.index(x)
        for i in range(ab,len(lst),1):
            num=lst.index(ab)
            num=num lst[i]
            print(num)
    return num
        
    
y=input("Enter a number present in the list: ")
print(func(y))

Above is the function to find all numbers and sum from index m. It takes a number from the user,gets the index and prints the sum of the number from index m. But the code output is 0 in this case

CodePudding user response：

First of all, you can use split() with empty parameter.

And a solution of your problem is:

    def func(x):
    a=input("Enter list of Numbers: ")
    lst=list()
    for i in a:
        try:
            i=int(i)
            lst.append(i)
        except:
            pass
    num=0
    x=int(x)
    for i in (lst):
        if x==i:
            index=lst.index(x)
            for i in range(index,len(lst),1):
                num=num lst[i]
    return num
        
        
    
y=input("Enter a number present in the list: ")
print(func(y))

instead of map i have used the for loop to covert the string to a integer list. then if x==i i searched the index of x in the list and from the index i start to sum the numbers again using a for loop.

CodePudding user response：

Try:

def func(y, lst):
    try:
        return sum(lst[lst.index(y):])
    except ValueError:
        print(f"{y} is not in {lst}")

lst = list(map(int,input("Enter a list of numbers: ").split()))
y = int(input("Enter a number present in the list: "))
total = func(y, lst)
print(total)

Output:

Enter a list of numbers: 10 20 30 40 50 60
Enter a number present in the list: 30
180