What is the equivalent of JavaScript's `===` in Python, if it's not `is`?-CodePudding

In JavaScript, if I want to know if foo == false and foo != 0 (or some other "falsy" value), I use foo === false, and that gives me a nice simple, exact comparison. It's even computationally faster because it doesn't try to test multiple types of equivalence. In Python the only equivalent I found to === and !== was is and is not. Now, after getting the SyntaxWarning: "is" with a literal. Did you mean "=="? error, and reading questions, answers, and articles about why is shouldn't be used in this, I'm left scratching my head.

For example:

def foo(bar=False):
    if bar != False:
        print(bar)
    else:
        print('default!')

Of course I ran into a case where bar was set to 0 and printed default!. I had been dealing with it like so:

def foo(bar=False):
    if bar is not False:
        print(bar)
    else:
        print('default!')

So if I'm not supposed to do that, what's the correct approach? Do I need to type out bar != False and bar != 0 every time?

CodePudding user response：

One option is :

def foo(bar=None):
    if bar is not None:
        print(bar)
    else:
        print('default!')

Only the 'None' object is identical to 'None' so any value of bar except None will print 'default'