How to convert XFile to File to upload an image to remote server?-CodePudding

I need to upload a picture taken with the device´s camera.

Here you have the code:

   XFile? _image;

  Future getImagefromcamera() async {
    XFile? image = await ImagePicker().pickImage(source: ImageSource.camera);
    setState(() async {
      _image = image ;
      conFoto = true;
      File file = File(image?.path);
      _upload(file);
    });
  }

 void _upload(File file) {


    if (file == null) return;
    setState(() {


    });
    String base64Image = base64Encode(file.readAsBytesSync());
    String fileName = file.path.split("/").last;

    http.post(Uri.parse(phpEndPoint), body: {
      "image": base64Image,
      "name": fileName,

    }).then((res) async {
      print(res.statusCode);
      setState(() {
        print("***********SOURCE subido:" fileName);


      });
    }).catchError((err) {
      print(err);
    });
  }

I am getting an error at line

 File file = File(image?.path);

Error: The argument type 'String?' can't be assigned to the parameter type 'String'

CodePudding user response：

The problem here is, the XFile in your case the image variable can be null. So if it is null then it's not possible to get a path from it and make a file.

So just need to little null check. By doing this

File file = File(image?.path? ?? "");

Which says, if the path string doesn't exist, the use the empty string. Or if you are supper confident that image file will definitely exist, then what you can do is, this

File file = File(image!.path);

In this case, your function will throw an error if the image file doesn't exist.