i use the following regex to extract values that appear before certain units:

([.\d] )\s*(?:kg|gr|g)

What i want, is to include the unit of that specific value for example from this string :

"some text 5kg another text 3 g more text 11.5gr end"

i should be getting :

["5kg", "3 g", "11.5gr"]

can't wrap my head on how to modify the above expression to get the wanted result. Thank you.

CodePudding user response：

import re

p = re.compile('(?<!\d|\.)\d (?:\.\d )?\s*?(?:gr|kg|g)(?!\w)')
print(p.findall("some text 5kg another text 3 g more text 11.5gr end"))

CodePudding user response：

Other solution (regex demo):

(?i)\b\d \.?\d*\s*(?:kg|gr?)\b

• (?i) - case insensitive
• \b - word boundary
  • \d \.?\d* - match the amount
  • \s* - any number of spaces
  • (?:kg|gr?) - match kg, g or gr
• \b - word boundary

import re

p = re.compile(r"(?i)\b\d \.?\d*\s*(?:kg|gr?)\b")
print(p.findall("some text 5kg another text 3 g more text 11.5gr end"))

Prints:

['5kg', '3 g', '11.5gr']