Regex for replacing {{}} with {{{}}} conditionaly-CodePudding

In a large string, some words wrap by {{ }} in three ways:

 1. {{some words}}
 2. {{#some words}}
 3. {{/some words}}

I need a solution that wraps matches in an extra pair of braces, but it should happen just for the first case, and not for the other two. Only {{some words}} should be replaced to {{{some words}}}.

Currently, I have this code:

const text = "text {{#some words}} text {{some words}} text";
const newText = text.replaceAll("{{", "{{{").replaceAll("}}", "}}}");
console.log(newText);

But this does not take the restriction into account, and wrongly adds parentheses around {{#some words}}, which should remain unchanged.

Is there any solution, possibly with a regular expression?

CodePudding user response：

You can use [^#/] to match any character that is not # and / and use that in the overal regular expression:

let text = "{{hello}} {{#hello}} {{/hello}} {{world}} {{#world}} {{/world}}";
let result = text.replace(/\{\{[^#/].*?}}/g, "{$&}");
console.log(result);

.*? matches any character (except newline) in a lazy manner, i.e. it will stop matching when }} is encountered.
$& represents the complete matched string

CodePudding user response：

Use this

const replacing = (word) => {
  return word.replace(/\{\{([a-zA-Z0-9 ] )\}\}/g, ((a,b) => `{{{${b}}}`))
}

console.log(replacing("{{some Words}}"))
console.log(replacing("{{#some words}}"))
console.log(replacing("{{/some words}}"))