table :
| a |
|---|
| 1 |
| 4 |
| 8 |
| 9 |
desired output
| a |
|---|
| 3 |
| 4 |
| 1 |
CodePudding user response:
You can use lead to get the value of a from the next row (ordered by a):
select * from
(select lead(a) over(order by a) - a as a
from table_name) t
where a is not null;
We will create a temp table where the first row will be missing and the row number will adjust like that:
Select ROW_NUMBER() over(order by a) as rn, cte.a From cte Where cte.rn != 1
Output:
Finally will just join the table using the rn and substruct the value
With cte as( Select ROW_NUMBER() over(order by a) as rn, cte.a From cte Where cte.rn != 1 ) cte_2 as( Select ROW_NUMBER() over(order by a) as rn, cte.a From cte Where cte.rn != 1 ) Select ABS(cte.a - cte_2.a) as sub From cte join cte_2 on cte.rn = cte_2.rn



