Regex: Find words starting with # symbol-CodePudding

Could someone help to write regex in order to get the list of matched words like below? Words that start with the '#' symbol are references, so I need to grab them through the expression and do further work with them. References could only be alphanumeric and always starts with the '#' symbol. References can be preceded and/or followed by space, - / * & ^ symbols.

Examples:

'=#CELL1 2-#TABLE3' => Result of exec method: ["#CELL1", "#TABLE3"]
'= 1 #MyInput & #BillingAmount' => Result of exec method: ["#MyInput", "#BillingAmount"]
'#input1=TODAY()*3 #daily' => Result of exec method: ["#input1", "#daily"]

CodePudding user response：

Please don't use a loop when there is String.match, you can use regex with global flag to find each case, below I made a solution by joining all inputs in a string but you can use it in separate strings.

const input = `
=#CELL1 2-#TABLE3
= 1   #MyInput & #BillingAmount
#input1=TODAY()*3   #daily
`;

console.log(
  input.match(/#\w /g)
);

CodePudding user response：

const regex = /(\#\w )/gm;
const str = `'#input1=TODAY()*3   #daily'`;
let m;

while ((m = regex.exec(str)) !== null) {
    // This is necessary to avoid infinite loops with zero-width matches
    if (m.index === regex.lastIndex) {
        regex.lastIndex  ;
    }
    
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}