Do I need to look for a key down and up event to avoid double occurrence of my else block?-CodePudding

Wondering why its printing my else statement twice in this scenario. In theory it should just execute it once after an incorrect key is read, and loop back. the out put I am getting after pressing a non 'enter' key How can I avoid this?

import random
import keyboard

#Constant values to assign as a win or loss
_WIN = 1
_LOSE = 0

#Create and store game hand choices
handChoice = ['Spock', 'Lizard', 'Rock', 'Paper', 'Scissors']

print('\nThis is advanced Rock, Paper, Scissors! Press ENTER to start the automated game->')
while True:
    if keyboard.read_key() == 'enter':
        break
    else:
        print('Please press ENTER!')

#Hand choices randomly assigned to player 1
player1 = random.choice(handChoice)
print('Player 1 uses '   player1   '!\n')

CodePudding user response：

Looking true the docs you could use this:

keyboard.wait('enter')

It will also use less cpu. But you would need the async library with timeout to also give output. you could also use this:

while True:
    if keyboard.read_key() == 'enter':
        break
    elif event.event_type == keyboard.KEY_DOWN:
        print('Please press ENTER!')