I am doing a program of say digit in python using recursion and i want that if digit==0 return nothing.

Code:

# Q1
    # Say digit 
    # i/p = 412 - o/p = four one two

list = ['zero','one','two','three','four','five','six','seven','eight','nine']
n=412

def say_digit(n, list):
    if n==0:
        return ''

    digit = int(n % 10)
    n = n / 10

    say_digit(n, list)
    print(list[digit], end=' ')
    return ''

if __name__ == "__main__":
    n=int(input("Enter Number: "))
    ans = say_digit(n, list)
    print(ans)

Output:

CodePudding user response：

Use // instead of /

i.e. n = n // 10

/ gives float and // gives int

CodePudding user response：

The code does a division by 10 at each iteration. But there's no guarantee this will reach 0. In Python3, it does a floating point division. You can get to 0 with integer division (using // instead of /).

Here's an updated version:

# Q1
    # Say digit
    # i/p = 412 - o/p = four one two

numbers = ['zero','one','two','three','four','five','six','seven','eight','nine']
n=412

def say_digit(n, numbers):
    if n==0:
        return ''
    digit = int(n % 10)
    n = n // 10

    return say_digit(n, numbers)   ' '   numbers[digit]

if __name__ == "__main__":
    n=int(input("Enter Number: "))
    ans = say_digit(n, numbers)
    print(ans)

It also translates each digit in the words from list.

Ideally, one shouldn't shadow built-in names like 'list'. To avoid that, this version uses the name 'numbers'.