Question, count is increamenting, how do i excute a statment each time count adds 2 or 5. Assuming i'm working with a large list of about 1000 or more entries and i want to excute a different statment each time count gets 10, how do i do that?
count = 0
for x in range(10):
count = 1
if count == 2:
print(f'count is now {count}')
CodePudding user response:
I think that the question is a version of the famous FizzBuzz algorithm:
def fizzbuzz(n):
for count in range (n):
if x % 10 == 0:
print("fizzbuzz")
elif x % 2 ==0:
print("fizz")
elif x % 5 == 0:
print ("buzz")
else:
print (x)
CodePudding user response:
count = 0
for count in range(1000):
count = 1
if count == 0: #if count is multiple of 10, say hello
print(f'Hello')
else: #else count normally
print(f'count is now {count}')
