x = [1,2,3,0,0,0]

This is the code I have used and it is not removing last zero it is skipping for I in x: if I==0: x.remove(I) print(x)

output: [1, 2, 3, 0] so from the output the last zero is not removing whystrong text

CodePudding user response：

Why don't you use this simple list comprehension.

x = [1,2,3,0,0,0]
y=[i for i in x if i != 0]
print(y)

You'll get a new list (y) with the 0 removed, while the x is preserved in it's original state.

[1, 2, 3]

Process finished with exit code 0

For more study on list.remove(), check this List.remove() does not remove all occurrances

CodePudding user response：

As per documentation, list.remove removes first element whose value matches given number.

So, when first '0' at index 3 is removed, the new list is [1,2,3,0,0] with the list iteration index at 4. The following 0 (which was at index 4 in original list) moves back one place and is getting skipped. This can be seen with following code:

x = [0,0,0,0,0,0]
for id, i in enumerate(x):
 print(id, i)
 if i == 0:
  print(x, i)
  x.remove(i)

In this, every second element is missed, and final x is [0, 0, 0]

As for what is correct way to do this, list comprehension is a good way, as answered by Anand: x = [i for i in x if i!=0]