Why don't the first error, the second error

CodePudding user response:

Cout needs a parameter, and returns the stream itself, so the cout & lt; & lt; , can together (the red part of the return flow, blue part of the flow and return flow can be directly used, so the green part also can use)
But
CoutThe second piece of code is equivalent to (cout CodePudding user response:

reference 1st floor qybao response:

cout needs a parameter, and returns the stream itself, so the cout & lt; & lt; , can together (the red part of the return flow, blue part of the flow and return flow can be directly used, so the green part also can use)
But
CoutThe second piece of code is equivalent to (cout

The first result is 10 (excuse me? - man -?)
Because c is not flow

CodePudding user response:

refer to the second floor m0_51247563 response:

Quote: refer to 1st floor qybao response:

cout needs a parameter, and returns the stream itself, so the cout & lt; & lt; , can together (the red part of the return flow, blue part of the flow and return flow can be directly used, so the green part also can use)
But
CoutThe second piece of code is equivalent to (cout

The first result is 10 (excuse me? - man -?)
Because c is not flow

yes, cout<10 a output, c

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