How to convert a stream to another type without using map?-CodePudding

I've this code:

Stream<int> get fooStream async* {
  barStream.listen((_) async* { 
    int baz = await getBaz();
    yield baz; // Does not work
  });  
}

How can I return Stream<int> from another stream?

Note: If I use map to transform the stream, then I'll have to return Stream<Future<int>>, but I want to return Stream<int>. I also don't feel like using rxdart pacakge for this tiny thing.

CodePudding user response：

Use asyncMap.
```
barStream.asyncMap((e) => getBaz())
```

Use await for

Stream<int> get fooStream async* {
 await for (final item in barStream) {
   yield await getBaz();
 }
}