I need to run a Bash command with a script calling parameters: comm1 ./script.sh param1 param2 param3. Script includes this: timeout 10 bash -c " comm2 ./param1.param3". It indicates that param1 file is in the current directory.

And it works as long as param1 is a single word. But I need it to be a file name which can have spaces. So command should be: comm1 ./script.sh "param1\ with\ space" param2 param3 . No dot and extension in file name, just spaces are problem and maybe brackets.

I don't know how to modify param1 to be able to use spaces in this case, and if script should also be modified. Thanks for help.

CodePudding user response：

Instead of trying to quote and escape the parameters, send the parameters to bash -c.

timeout 10 bash -c 'comm2 "$@"' bash "$1" "$2"

This will set $0 to "bash" and the first two parameters to the values of the first two positional parameters of the script.

CodePudding user response：

I'm a bit unsure on the exact reason to call bash first.

The easiest answer is to simply skip the bash call:

timeout 10 comm2 "./param with.spaces" param2

If you want to reuse the logic in several places, make a function.

timesup() { timeout 10 "$@" ;}

timesup comm2 "./param with.spaces" param2

whatever command you throw, the function will parse it the same way

If you really need to call bash first for whatever reason, you could mix quotation:

timeout 10 bash -c "comm2 './param with.spaces' param2"