How to store an 'args.foo' value to a 'bar' variable?-CodePudding

I have been using the argparse for my latest project and although it is extremely helpful, I have realized that most of the time, especially in longer scripts, I try to avoid using the variable with the 'args.' prefix, so lines like this are bloating my code:

parser.add_argument('--learning_rate', '--lr', default=0.0005, type=float, help='defines the learning_rate variable for the model.')
learning_rate = args.learning_rate

is there an option to automatically store the content passed to --learning_rate into learning_rate, avoiding this second line of code?

Thanks for your time and attention.

CodePudding user response：

When you call a function, an argument is implicitly assigned to a parameter.

In the same scope where args is defined, I would continue using args.learning_rate to emphasize that it is a configuration option. But instead of writing

def foo(x):
    return x * args.learning_rate

y = foo(3)

write

def foo(x, learning_rate):
    return x * learning_rate

y = foo(args.learning_rate)

When reading the definition of foo, you don't care how learning_rate will be set at call time.