from matplotlib.finance import quotes_historical_yahoo_ochl as getData
import scipy as sp
ticker='IBM'
begdate=(2013,9,1)
enddate=(2013,11,11)
data= getData(ticker, begdate, enddate,asobject=True, adjusted=True)
p=data.aclose
d=sp.diff(p)
cov_=sp.cov(d[:-1],d[1:])
if cov_[0,1]<0:
print("Roll spread for ", ticker, 'is', round(2*sp.sqrt(-cov_[0,1]),3))
else:
print("Cov is positive for ",ticker, 'positive', round(cov_[0,1],3))
My effort is to calculate the above code in Python but since matplotlib.finance has been deprecated I tried another road using pandas_datareader.data.
Doing so I made this one :
import pandas_datareader.data as web
end = '2013-11-11'
start = '2013-09-01'
get_px = lambda x: web.DataReader(x, 'yahoo', start=start, end=end)['Adj Close']
symbols = ['IBM']
data = pd.DataFrame({sym:get_px(sym) for sym in symbols})
data = data.rename({'IBM': 'Adj Close'}, axis=1)
p1 = data.dropna()
p = np.asarray(p1);p
d = np.diff(p);d
cov_= np.cov(d[:-1],d[1:])
cov_
I receive an error
/opt/anaconda3/lib/python3.8/site-packages/numpy/lib/function_base.py:380: RuntimeWarning: Mean of empty slice.
avg = a.mean(axis)
RuntimeWarning: Mean of empty slice.
if cov_[0,1]<0:
print("Roll spread for ", symbols, 'is', round(2*sp.sqrt(-cov_[0,1]),3))
else:
print("Cov is positive for ",symbols, 'positive', round(cov_[0,1],3)
What is my mistake ? I don’t know in the first code what type of object the data object is.And probably there is where the problem starts.
Updated
The line code
d = np.diff(p);d
is empty.The result is :
array([], shape=(50, 0), dtype=float64)
The needed result is the 1.136
CodePudding user response:
Using your code, the shape of p is wrong:
p.shape
Out[8]: (50, 1)
When you apply np.diff() onto this, it applies the difference on every entry, instead of across the vector as you intended, hence the error.
You can do something like this:
p = p1['Adj Close'].ravel()
d = np.diff(p)
cov_= np.cov(d[:-1],d[1:])
cov_
array([[ 3.12100146, -0.15854027],
[-0.15854027, 3.20098506]])
Not very sure how you define the roll, I think:
np.sqrt(abs(cov_))
array([[1.76663563, 0.39817116],
[0.39817116, 1.78912969]])
What you need to get 1.766 is:
np.sqrt(abs(cov_))[0,0]

