Python string mutation-CodePudding

I am trying to loop though a string and convert underscores to camel case. Example) my_string --> myString

I have posted my working code below. Can someone help me figure out the hole in my logic?

            
def to_camel_ca (string):
    camel_string = ""
    for i in range(len(string)):
        if string[i] == '_':
            camel_string = camel_string   string[i   1].replace(string[i 1], string[i 1].capitalize())
        elif string[i] != "_":
            camel_string = camel_string   string[i]
        print(camel_string)
    return camel_string
    
    
to_camel_ca('my_string') 



#returns

m
my
myS
mySs
mySst
mySstr
mySstri
mySstrin
mySstring

'mySstring'

Many thanks!

CodePudding user response：

Notice that the camelCase string will be shorter. When you encounter an underscore, and capitalize the next letter, you need to skip a letter in the source string. Here is a way to do that:

def to_camel_ca (string):
    camel_string = ""
    skip = False
    for i in range(len(string)):
        if skip:
            skip = False
            continue
        if string[i] == '_':
            camel_string = camel_string   string[i   1].replace(string[i 1], string[i 1].capitalize())
            skip = True
        elif string[i] != "_":
            camel_string = camel_string   string[i]
        print(camel_string)
    return camel_string

Example

to_camel_ca('my_test_string')

m
my
myT
myTe
myTes
myTest
myTestS
myTestSt
myTestStr
myTestStri
myTestStrin
myTestString

A Slightly Different Approach

Here's is a slightly simpler approach. When an underscore is encountered, make a note to capitalize the next letter. It has the advantage of handling input strings which end in underscore.

def to_camel_ca (string):
    camel_string = ""
    capitalize = False
    for i in range(len(string)):
        if string[i] == '_':
            capitalize = True
            continue
        elif capitalize:
            camel_string = camel_string   string[i].capitalize()
            capitalize = False
        elif string[i] != "_":
            camel_string = camel_string   string[i]
        print(camel_string)
    return camel_string

CodePudding user response：

The problem is that a character after an underscore is processed/added to the camelString twice: one when the if finds and underscore and again when that character itself matches the elif condition.