How to compare timedelta object with time object in python-CodePudding

I had one time object I used timedelta to add 5 hours and 30 minutes to it now I have one timedelta object

new_time2 = timedelta(hours=starttime_time.hour 5, minutes=starttime_time.minute 30)
print(new_time2, type(new_time2))
>>>15:30:00 <class 'datetime.timedelta'>

Now I have another time object

input_time = "09:30:00"
a = datetime.strptime(input_time, '%H:%M:%S').time()
print(a, type(a))
>>>09:30:00 <class 'datetime.time'>

So I want to compare these two times but when I am doing this I am getting a TypeError

print(new_time2 >= a)

TypeError: '>=' not supported between instances of 'datetime.timedelta' and 'datetime.time'
09:30:00 <class 'datetime.time'>

So is there any other way I can compare these two times. Thanks in advance.

CodePudding user response：

You can convert the time instance to timedelta:

>> from datetime import timedelta
>>> e = timedelta(hours=a.hour, minutes=a.minute, seconds=a.second)
>>> print(e, type(e))
9:30:00 <class 'datetime.timedelta'>

then you can compare:

>>> print(new_time2 >= e)
True

CodePudding user response：

you created a timedelta object and not a datetime object.. let me give you an example :

>>> from datetime import datetime, timedelta
>>>
>>> t1 = datetime.now()
>>> t1
datetime.datetime(2022, 1, 11, 13, 34, 37, 537863)
>>>
>>> tenMinsDelta = timedelta(minutes=10)
>>>
>>> t1PlusTen = t1   tenMinsDelta
>>>
>>>
>>> type(t1PlusTen)
<class 'datetime.datetime'>
>>>
>>> type(tenMinsDelta)
<class 'datetime.timedelta'>

So, instead of doing:

new_time2 = timedelta(hours=starttime_time.hour 5, minutes=starttime_time.minute 30)

you must:

delta = timedelta(hours=5, minutes=30)

new_time = starttime_time   delta