Is there a way to pass an empty std::span<int> to a function?
I have a function like below:
bool func( const std::vector<int>& indices )
{
if ( !indices.empty( ) )
{
/* do something */
}
...
}
// when calling it with an empty vector
const bool isAcceptable { func( std::vector<int>( 0 ) ) };
And I want to change it to use std::span instead of std::vector so that it can also get std::array and raw array as its argument.
Now here:
bool func( const std::span<const int> indices )
{
if ( !indices.empty( ) )
{
/* do something */
}
...
}
// when calling it with an empty span
const bool isAcceptable { func( std::span<int>( ) ) }; // Is this valid code?
Also does std::span properly support all contiguous containers (e.g. std::vector, std::array, etc.)?
CodePudding user response:
std::span's default constuctor is documented as:
constexpr span() noexcept;Constructs an empty span whose
data() == nullptrandsize() == 0.
Hence, passing a default constructed std::span<int>() is well-defined. Calling empty() on it is guaranteed to return true.
Does
std::spanproperly support all contiguous containers (e.g.std::vector,std::array, etc.)?
Basically, std::span can be constructed from anything that models a contiguous and sized range:
template<class R> explicit(extent != std::dynamic_extent) constexpr span(R&& range);Constructs a span that is a view over the range range; the resulting span has
size() == std::ranges::size(range)anddata() == std::ranges::data(range).
In particular, std::vector does satisfy these requirements.
For C-style arrays and std::array there are special constructors (to harness their compile-time size):
template<std::size_t N> constexpr span(element_type (&arr)[N]) noexcept; template<class U, std::size_t N> constexpr span(std::array<U, N>& arr) noexcept; template<class U, std::size_t N> constexpr span(const std::array<U, N>& arr) noexcept;Constructs a span that is a view over the array
arr; the resulting span hassize() == Nanddata() == std::data(arr).
