The following works but feels ugly when I do the (*this)(5) part.
struct MyStruct
{
void operator()(int a)
{
// Do something with "a"
}
void myFunc()
{
(*this)(5);
}
};
I will need to overload the () operator and use it from within other class methods.
CodePudding user response:
You have a few options:
(*this)(5)this->operator()(5)or just
operator()(5)Create a method that you call from within the
operator(), e.g.:void do_work(int a) { /* ... */ } void operator()(int a) { do_work(a); } void myFunc() { do_work(); }
Whichever you choose is just a matter of personal taste.
