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compiled = re.compile(r'\\\d\\\d')
compiled.match("\3\3")
as of my understanding first two backslash will match one backslash in searched string and \d will match one number. why not this string able to match regex?

CodePudding user response：

you should save the matched results in a variable: matched = compiled.match("\3\3"). Please refer to this article

CodePudding user response：

Use raw string to prevent "\3" from being escaped

compiled = re.compile(r'\\\d\\\d')
compiled.match(r"\3\3")